Question

find the least Number which when divided
by 6, 15, and 18 leaves bemainder 5 in
Cach
case​

Answer 1

Answer:

  95

Step-by-step explanation:

Find least common multiple i.e. L.C.M  of 6, 15 , 18

L.C.M(6, 15 ,18) = 90

which is the smallest no divisible by all given numbers 6 , 15 , 18

so to get remainder as 5 just add 5 to 90 i.e. 90+5 = 95

hence , 95 is the lest number which when divided by 6 , 15 , 18 leaves remainder 5 in each case.