Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in case. please answer me
Answers
Answered by
1
Answer:
95
Step-by-step explanation:
95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case.
Answered by
0
Answer:
Below is the LCM shown for 6,15 and 18 using prime factorization.
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
Thus, the LCM of 6,15 and 18 = 2 × 3 × 3 × 5 = 90
Now, adding 5 to 90, we get 90 + 5 = 95
Verification:
1) 95/6
Quotient = 15
Remainder = 5
2) 95/15
Quotient = 6
Remainder = 5
3) 95/18
Quotient = 5
Remainder = 5
Hence, 95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case.
Step-by-step explanation:
MARK ME BRAINLIEST
Similar questions