Math, asked by srishasp10, 7 hours ago

Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in case. please answer me​

Answers

Answered by foram2712
1

Answer:

95

Step-by-step explanation:

95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case.

Answered by ItzSiddhi3009
0

Answer:

Below is the LCM shown for 6,15 and 18 using prime factorization.

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

Thus, the LCM of 6,15 and 18 = 2 × 3 × 3 × 5 = 90

Now, adding 5 to 90, we get 90 + 5 = 95

Verification:

1) 95/6

Quotient = 15

Remainder = 5

2) 95/15

Quotient = 6

Remainder = 5

3) 95/18

Quotient = 5

Remainder = 5

Hence, 95 is the least number which when divided by 6, 15, and 18 leaves a remainder of 5 in each case.

Step-by-step explanation:

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