Math, asked by aakash2617, 6 months ago

find the least number which when divided by 6,7,8,9,10 leaves 1,2,3,4,5,remainders respectively but when divided by 19 leaves no remainder

Answers

Answered by mananmadani53
0

Answer:

As the remainder is same. Required number = LCMofdivisors+Remainder =LCM(6,7,8,9,10)+1 =2520+1 =2521.

Step-by-step explanation:

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