Find the least number which when divided by 6, 7, 8, 9, 10 leaves remainder 1
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The number itself remains the remainder 1
for eg: 6 divided by 6 leaves the remainder 1 and so on
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as the remainder is same
required number =LCM of divisors +remainder
=LCM(6,7,8,9,10)+1
=2520+1
=2521
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