find the least number which when divided by 6 7 8 9 and 12 leaves the remainder 1 in each case
Answers
Answered by
4
Answer:
Required number = (L.C.M OF 6,7,8,9,12) + 1
L.C.M of 6,7,8,9,12=504 = 504+1=505
Answered by
2
Answer:505
Step-by-step explanation:
There is an easy method to solve these type of questions
We find the L.C.M. of all the given divisors ( here, 6,7,8,9,12) and add 1 to it.
So it is L.C.M. +1
HERE THE L.C.M. is 504
So the least number will be 505.
It would also make sense if you try to think about the method intutuively
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