Math, asked by rehana366, 10 months ago

find the least number which when divided by 6 7 8 9 and 12 leaves the remainder 1 in each case

Answers

Answered by chakshitij
4

Answer:

Required number = (L.C.M OF 6,7,8,9,12) + 1

L.C.M of 6,7,8,9,12=504 = 504+1=505

Answered by arth9979
2

Answer:505

Step-by-step explanation:

There is an easy method to solve these type of questions

We find the L.C.M. of all the given divisors ( here, 6,7,8,9,12) and add 1 to it.

So it is L.C.M. +1

HERE THE L.C.M. is 504

So the least number will be 505.

It would also make sense if you try to think about the method intutuively

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