Question

find the least number which when divided by 6 7 8 9 and 12 leaves remainder 3 in each case​

Answer 1

504 is the least number which divides 6,7,8and12 which leaves remainder 3 in each case
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Answer 2

Answer:

507

Step-by-step explanation:

writing the prime factorization:

6=2×3

7=1×7

8=2×2×2

9=3×3

12=2×2×3

the least common multiple therefore is:

2×7×2×2×3×3=504

so numbers which on being divided by 6,7,8,9 & 12 leave a reminder 3 are : 504+3= 507