Question

Find the least number which when divided by 6;7;8;9 and 12 leaves the same remainder 2 in each case.​

Answer 1

504 is the least number exactly divisible by 6,7,8,9 and 12. Hence, least number which when divided by 6,7,8,9 and 12 leaves remainder 2 in each case=504+2=506.

Answer 2

Answer:

Step-by-step explanation:

LCM (6, 7, 8, 9 12) = 504

So, 504 is the smallest number that leaves 0 as the remainder each time when divided by any of 6, 7, 8, 9, and 12.

So, the required number = (504 + 2) = 506

∴ 506 will be the smallest number which when divided by 6, 7, 8, 9, and 12 leaves the remainder 2 each time.