Math, asked by sankrish4907, 10 months ago

Find the least number which when divided by 8,10 ,12 leaves reaminder 5 in each case

Answers

Answered by vedsinghh8
0

Answer:

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Answered by aashritha9696
0

Answer:

Step-by-step explanation:8 = 2x2x2

15 = 3x5

20 = 2x2x5

21 = 3x7

30 = 2x3x5

LCM = 2x2x2x3x5x7 = 840.

Next add 5 to 840 to 845 as the number you are seeking.

Check: 845/8 = Quotient = 105, Remainder = 5. Correct.

845/15 = Quotient = 56, Remainder = 5. Correct.

845/20 = Quotient = 42, Remainder = 5. Correct.

845/21 = Quotient = 40, Remainder = 5. Correct.

845/30 = Quotient = 28, Remainder = 5. Correct.

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