Find the least number which when divided by 8, 12, 15 and 18 leaves a remainder 3 in each case and exactly divisible by 11.
Answers
Answered by
0
Answer:
- 8-3=5
- 12-3=9
- 15-3=12
- 18-3=15
- 11-0=11
- LCM OF 5,9,12,15,11
- = 3×5×3×4×11
- = 198O Ans.
Answered by
0
Ans:-363 is exactly divisible by 11
Attachments:
Similar questions