Question

Find the least number which when divided by 8,14,20,25 leaves 4 as remainder in each case

Answer 1

Answer:

1404

The least number which when divide by 8,14,20,25 and leaves 4 as remainder in each case is 1404.

Step-by-step explanation:

here is u r answer...

mark me as brainliest...

hope this will help u...

Answer 2

Answer:

1404

Step-by-step explanation:

L.C.M. of 8,14,20, and 25

8 = 2*2*2

14 = 2*7

20 = 2*2*5

25 = 5*5

L.C.M. of 8,14,20, and 25= 2*2*2*5*5*7 = 1400

Now,

4+1400 = 1404

Hence, 1404 is the least number which when divided by 8,14,20, and 25 leaves a remainder 4 in each case.

________________________________________

Verification:

1) 1404/8

Quotient = 175

Remainder = 4

2) 1404/14

Quotient = 100

Remainder = 4

3) 1404/20

Quotient = 70

Remainder = 4

4) 1404/25

Quotient = 56

Remainder = 4

So, the required number is 1404.