Find the least number which when divided by 8, 9, 10, 15 and 20 leaves thesame remainder 5 every time.
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2
Answer:
365
Step-by-step explanation:
Taking the LCM of all the numbers together, we get the LCM as 360. then add 5 to it. then you can get the remainder as 5 each time. That is 360+ 5= 365
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Answered by
2
answer is 356
take the LCM of all number
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