Find the least number which when divided by 9 , 15, 18 leave remainder 5 in each case
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9 = 3 × 3
15 = 3 × 5
18 = 3 × 8
LCM = 3 × 3 × 5 × 8
=> 9 × 40
=> 360
Required number is ( 360 + 5 ) = 365
15 = 3 × 5
18 = 3 × 8
LCM = 3 × 3 × 5 × 8
=> 9 × 40
=> 360
Required number is ( 360 + 5 ) = 365
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4 divisible to all and remainder 5
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