Find the least number which when divided by 98 and 10 vi with live in each case the same remainder 10
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...here is ur answer mate.
Now taking the LCM of 98 and 105;
It is 2*3*5*7*7=1470;
As per the question by dividing the number by 98 and 105, get 10 as remainder;
So adding 10 in to 1470;1
1470+10=1480; Is the number which will leave a 10 remainder in both the case.
15*98+10=1480
14*105+10=1480
1470 is completely divisible by 98 and 105
hope it will help u..
mark as brainliest pls..
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