Math, asked by priyamegha04, 7 months ago

Find the least number which when divided separately by 15,20,36 and 48 leaves 3 as remainder in each case

please guys tell me bye process

Answers

Answered by Anonymous

1

LCM of 15,20,36 and 48 is 720. Hence the least number that leaves a remainder of 3 in each case is 720+3=723.

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