Find the least number which when divided separately by 15, 20, 36 and 48 leaves 3 as remainder in each case.
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Answered by
0
Answer:
This is a question of HCF, LCM.
the answer will be LCM(15,20,36,48) + 3.
So, the LCM of (15,20,36,48) is 1440.
The required number is 1443.
Answered by
3
Answer:
LCM of 15,20,36 and 48 is 720. Hence the least number that leaves a remainder of 3 in each case is 720+3=723.
Step-by-step explanation:
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