Question

find the least number which when dividelly bu 27 30 and 90 leaves remainder of 9 each case​

Answer 1

Question

Find the least number which when divided by 27, 30 and 90 leaves remainder of 9 each case.

Answer

Given:The number when divided by 27, 30 and 90 leaves remainder of 9 each case.

Consider from the Question

27 - 9 = 18

30 - 9 = 21

90 - 9 = 81

Therefore,

Let us find the LCM of 18,21 and 81.

The prime factorization of 18,21 and 81

18=2×3×3

21=3×3×3

81=3×3×3×3

The LCM is 1134

According to the question,The number when divided by 27, 30 and 90 leaves remainder of 9 each case.

Therefore the number is (1134+9) = 1143

Answer 2

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Step-by-step explanation:

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