Question

Find the least number which when dividend by 54,63and81 leves 6 remainder in each case

Answer 1

Your Question:

Find the least number which when dividend by 54,63 and 81 leaves 6 remainder in each case.

Step-by-step explanation:

Given,  

Find the least number which when divided by 54, 63 and 81 leaves 6 as remainder in each case

We need to find the LCM of the given numbers in order to find the least number. So  

LCM of 54, 63 and 81 will be

Factors are 3 x 3 x 3 x 2 x 7 x 3 = 1134 + 6 = 1140

Now when we divide 1140 / 54 remainder is 6

1140 / 63 remainder is 6

1140 / 81 remainder is 6

So the least number will be 1140

Answer 2

answer 1140

explanation

54=2 3 3 3

63=3 3 7

81=3 3 3 3

LCM = 2 3⁴ 7

LCM of 54 63 81 is 1134

1134 +6 = 1140