Math, asked by siddharthdullu3243, 1 year ago

Find the least number which when divides by 12,15 and 20 leaves as remainder in each care.

Answers

Answered by kaviya030204
1
Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
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