Question

Find the least number which when increased by 13 is divisible by 24, 60,156and 204​

Answer 1

Answer:

26507

Step-by-step explanation:

Let the number be "x".

x+13 is divisible by 24,60,156&204.

Finding HCF of 24,60,156&204:

we get 2×2×2×3×5×13×17=26520

now subtracting 13 from 26520

we get 26507.

increase 26507 by 13 you will get the number which is divisible by all of the given numbers.