Question

Find the least number which when increased by 17 is divisible by both 520 and 468

Answer 1

answer is 35
hope it's helps!!!!
pls give it brainliest

Answer 2

This kind of questions should be solved in this way:

Let the number be x.

The least number which is divisible by 520 & 468 will be LCM of 520 & 468.

Prime factorization of 520 = 2 * 2 * 2 * 5 * 13.

Prime factorization of 468 = 2 * 2 * 3 * 3 * 13.

LCM(520,468) = 2 * 2 * 2 * 3 * 3 * 5 * 13

                         = 4680.


Now, 

Given that the number is increased by 7.

x + 17 = 4680

x = 4680 - 17

x = 4663.



Therefore the least number = 4663.


Hope this helps!