Math, asked by raiutkarsh4525, 7 months ago

Find the least number which when increased by 21 is exactly divisible by 15,25,35 and 45.

Answers

Answered by dineshkumaryadav55
2

Step-by-step explanation:

let that number be X

According to question,

X + 21 = LCM of 15,25,35,45

LCM of 15 , 25 , 35 , 45 = 4725

x + 21 = 4725

x = 4725 - 21

x = 4704

required number is 4704

Answered by mili40379
3

Answer: the least number which when increased by 21 .Then I have find the number.

LCM of 15, 25,35,45 is 1575.

The least number is 1575 - 21 = 1554 (ans)

Step-by-step explanation:

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