Find the least number which when increased by 21 is exactly divisible by 15,25,35 and 45.
Answers
Answered by
2
Step-by-step explanation:
let that number be X
According to question,
X + 21 = LCM of 15,25,35,45
LCM of 15 , 25 , 35 , 45 = 4725
x + 21 = 4725
x = 4725 - 21
x = 4704
required number is 4704
Answered by
3
Answer: the least number which when increased by 21 .Then I have find the number.
LCM of 15, 25,35,45 is 1575.
The least number is 1575 - 21 = 1554 (ans)
Step-by-step explanation:
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