Find the least number which when increased by 3 is exactly divisible by 18 , 24 , 64 and 108.
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0
Answer:
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Answered by
2
Answer:
1725
Step by step explanation:-
First of all we must find the LCM of all the number
That is 1728
So we have found the number which is exactly divisible by 18, 24,64,108
Now the given condition is that when the number is increased by 3 it is divisible by the numbers given.
According to the condition 1728-3 = 1725
So we got our answer as 1725
If u wish to see how to find the LCM just check the attachment
Thank you...
1725
Step by step explanation:-
First of all we must find the LCM of all the number
That is 1728
So we have found the number which is exactly divisible by 18, 24,64,108
Now the given condition is that when the number is increased by 3 it is divisible by the numbers given.
According to the condition 1728-3 = 1725
So we got our answer as 1725
If u wish to see how to find the LCM just check the attachment
Thank you...
Attachments:
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