Math, asked by meghna, 3 months ago

Find the least number which when increased by 3 is exactly divisible by 18 , 24 , 64 and 108.​

Answers

Answered by roopraimanjitkaur
0

Answer:

sorry I didn't get okkkkkkkkkkl,

Answered by mathy48
2
Answer:
1725


Step by step explanation:-

First of all we must find the LCM of all the number
That is 1728

So we have found the number which is exactly divisible by 18, 24,64,108

Now the given condition is that when the number is increased by 3 it is divisible by the numbers given.
According to the condition 1728-3 = 1725

So we got our answer as 1725

If u wish to see how to find the LCM just check the attachment



Thank you...
Attachments:
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