Find the least number which when increased by 7 is exactly divisible by 15,20 and 25
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Answer:
293
Step-by-step explanation:
LCM of 15, 20 and 25 is 300
So the least number which when increased by 7 is exactly divisible by 15, 20 and 25 is ( 300 - 7 ) = 293.
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