Find the least number which when increased by 7is exactly divisible by 12 18 and 20
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First take LCM of 20,18, and 12
20= 2^2x5
18= 3^2x2
12=2^x3
LCM= 2^2x3^2x5
= 160
here it is least number when increased by 7.
So we need to SUBTRACT 7 from 160
Therefore, the answer is 153.
Hope it helps
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Answer:
The correct answer is in this pic. See
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