find the least number which, when increased by 9 is exactly divisible by 10, 12, 15 and 24.
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Answered by
4
Answer:
First we find the least number which is exactly divisible by the numbers 15,35 and 48 . For this , we find L.C.M of 15,35 and 48 .
∴ LCM =3×5×7×2 ×2×2×2=1680
According to given condition , the required number will be 15 less than 1680.
∴ The required least number =1680=15=1665
Answered by
1
Answer:
111
Step-by-step explanation:
111+9=120
120/10=12
120/12=10
120/15=8
120/24=5
that is the least possible number
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