Question

Find the least number which when increased by one is exactly divisible by 24, 32 and
40.​

Answer 1

Step-by-step explanation:

lcm of 24,32,40

$24 = 2 \times 2 \times 2 \times 3 \\ 32 = 2 \times 2 \times 2 \times 2 \times 2 \\ 40 = 2 \times 2 \times 2 \times 5$

lcm=480

required number =479