Question

find the least
number which will divide 40 50 and 60 leaves remainder 5 in each case

Answer 1

To find least no. which when divided by x,y and z leaves the same remainder 'r' in each case
Use approach as mentioned below:

Required no. = (LCM of x,y,z) + remainder

LCM( 40,50,60) = 3 * 5² * 2³=600
The required no. is 600+5=605

••••••Check=>
605=(40)*15+5
605 when divided by 40 gives 5 as a remainder

605=(50)*12+5
605 when divided by 50 gives 5 as a remainder

605=(60)*10+5
605 when divided by 40 gives 5 as a remainder

All gives 5 as remainder. Hence,Verified

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