Question

find the least numberwhich when divided by 27,35,45,and,49 leaves the remainder 6 in each case​

Answer 1

ANSWER:

• REQUIRED NUMBER = 6621

GIVEN:

• Numbers are 27,35,45 and 49

TO FIND:

• Number which when divided by 27,35,45,and,49 leaves the remainder 6 in each case.

SOLUTION:

Firstly we have to find the LCM of 27,35,45,and,49

=> 27 = 1*3*3*3

=> 35 = 5*7*1

=> 45 = 1*5*3*3

=> 49 = 1*7*7

LCM = 1*3*3*3*5*7*7

= 1*27*5*49

= 6615

• 27,35,45,and,49 divide 6615 Completely. Thus in order to get remainder 6 . We have to add 6 to 6615.
• REQUIRED NUMBER = 6615 + 6
• = 6621

NOTE:

some important formulas:

$\implies lcm \times hcf = product \: of \: two \: number$

• let a be any positive integer which is divided by b we get some quotient q and reminder r.
• (Representation). => a = bq+r