Question

find the least of square tiles required to pave the celling of a room 15m 17cm long and 9m 2cm broad

Answer 1

hii Mate___€ ^_^
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here's your answer_____⤵

☆it's given that;

♦length of room is 15m 17cm = 15 × 100+ 17 =1517cm.

♦__breadth of room = 9m 2cm = 902 cm.

then,

■ hcf of the 1517 and 902 will be size of square tiles;

---▶HCF of 1517 and 902 is 41cm .

•●Area of room = length x breadth

=》1517 × 902 cm^2

▪so, no. of tiles required = ( 1517 ×902) / (41×41)

--▶814 tiles

hence,__________________________________________
814 tiles are required to pave the celling of a room.

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