CBSE BOARD X, asked by hemantchouhan4522, 11 months ago

Find the least of square tiles which can cover the floor of a rectangular shape having length and breadth 16 metres 58 centimetres and 8 metres 32 centimetres respectively .

Answers

Answered by jaspreetsingh158
3

length of rectangular floor = 16m+58cm

=1658cm

breadth of rectangular floor=8m+32cm

=8032cm

now find the hcf (1658,8032)

i.e=1

=area of room

----------------------

area of tiles

l*b

-----

a^2

1658*8032

-------------------

2

=6658528

[the least no of tiles required is 6658528]


jaspreetsingh158: dont sure about ans
Answered by prakashkr852122
3

Answer:

I think this is wrong❌❌❌❌❌

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