Find the least of square tiles which can cover the floor of a rectangular shape having length and breadth 16 metres 58 centimetres and 8 metres 32 centimetres respectively .
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length of rectangular floor = 16m+58cm
=1658cm
breadth of rectangular floor=8m+32cm
=8032cm
now find the hcf (1658,8032)
i.e=1
=area of room
----------------------
area of tiles
l*b
-----
a^2
1658*8032
-------------------
2
=6658528
[the least no of tiles required is 6658528]
jaspreetsingh158:
dont sure about ans
Answered by
3
Answer:
I think this is wrong❌❌❌❌❌
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