Question

find the least perfect cube which is exactly divided by each of the number 4,6,9.​

Answer 1

Answer:

216. LCM of 4,6,9= 36. By Prime factorization we get. 36=2×2×3×3 . Clearly, to make it a perfect cube it must be ...

Answer 2

Answer:

(3*4*5*6)^2 = 129600

4=2*2

6=3*2

So we can divide by 4

32400 or 180^2

6=3*2 and we have 3 so can divide by 9

3600 or 60^2

Try dividing by 4

900/3 = yes

900/4 = yes

900/5 = yes

900/6 = yes

30^2 = 900

Step-by-step explanation:

Or

Using logic and the process of elimination rather than pure maths:

Looking at your stipulated factors tells me that the number must have its digits adding up to 3 (or a multiple thereof), and end in zero (this is because it must be an even number and divisible by 5). As the square number must end in zero, its square root must also end in zero. At a quick pot shot, I reckon 900 (30^2) is a reasonable candidate because 10^2 (100) and 20^2 (400) are not (digits don’t add up to a multiple of 3).