Find the least positive angle measured in degrees satisfying the equation sin cube x + sin cube 2 x + sin cube 3 X equal to sin x + sin 2x + sin 3x whole cube
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0 degree may be the correct answee
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Let sinx=a, sin2x=b, and sin3x=c
Expand out
(a+b+c)^ 3
Then subtract a^3,b^3 and c^3, which yields
3a^2b+3a^2c+3ab^2+6abc+3ac^2+3b^2c +3bc^2=0
The long expression can be factored nicely into :
3(a+b)(b+c)(a+c), which equal to 0.
The factor 3 makes no difference, so solve for:
sin(x)+sin(2x)=0 ,
sin(2x)+sin(3x)=0, and
sin(x)+sin(3x)=0,
Expand out
(a+b+c)^ 3
Then subtract a^3,b^3 and c^3, which yields
3a^2b+3a^2c+3ab^2+6abc+3ac^2+3b^2c +3bc^2=0
The long expression can be factored nicely into :
3(a+b)(b+c)(a+c), which equal to 0.
The factor 3 makes no difference, so solve for:
sin(x)+sin(2x)=0 ,
sin(2x)+sin(3x)=0, and
sin(x)+sin(3x)=0,
shaina66:
hi pglu
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