Question

find the least positive integer n for which (1+i/1-i)^n=1​

Answer 1

Given [(1+i)/(1-i)]n = 1

Multiply numerator and denominator with (1+i)

We get [(1+i)(1+i)/(1-i)(1+i)]n = 1

[(1+2i-1)/(1-i2)]n = 1

[(2i)/(1-(-1))]n = 1

(2i/2)n = 1

in = 1

Here the smallest number of n is 4.

Answer 2

Answer:

don't know

Step-by-step explanation:

Gegsgdgevdvgdgeveveg বিদ্যালয়ে বৃক্ষরােপণ অনুষ্ঠান নিয়ে একটি প্রতিবেদন রচনা করাে।