Find the least positive integer which is divisible by First 5 natural number
Answers
Answered by
3
We have to find the Least positive integer that is divisible by first 5 natural numbers.
First 5 natural numbers = 1 , 2, 3 , 4 and 5.
Prime factorization of 1 = 1
Prime factorization of 2 = 2
Prime factorization of 3 = 3
Prime factorization of 4 = 2 × 2
Prime factorization of 5 = 5
L.C.M = 1 × 2 × 2 × 3 × 5 = 60.
Hence, required number is 60.
First 5 natural numbers = 1 , 2, 3 , 4 and 5.
Prime factorization of 1 = 1
Prime factorization of 2 = 2
Prime factorization of 3 = 3
Prime factorization of 4 = 2 × 2
Prime factorization of 5 = 5
L.C.M = 1 × 2 × 2 × 3 × 5 = 60.
Hence, required number is 60.
Anonymous:
Mark as Brainliest plz...........
Answered by
1
60 is the answer................
Similar questions