Question

Find the least positive value of k for which X square + kx + 16 is equal to zero has real root​

Answer 1

Answer:

K = 8

Step-by-step explanation:

x2 + kx + 16 = (x+y) (x+(k-y))

So, here y × ( k -y) =16 and y+ (k-y)= k

we want least values so values can be :

y=4; k-y=4;

So k=8