find the least positive value of n of 1+i by 1-i whole power n equal to 1
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Multiply and divide numerator by (1+i), we get [(1+i)²/(1-i)(1+i)]ⁿ
= [(1-1+2i)/(1²+1²)]ⁿ = (i)ⁿ
So, we have (i)ⁿ = 1. The least positive value is n = 4
PS: mark me as brainlist
= [(1-1+2i)/(1²+1²)]ⁿ = (i)ⁿ
So, we have (i)ⁿ = 1. The least positive value is n = 4
PS: mark me as brainlist
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