Question

Find the least sq . no.which is divisible by each of the no.6,9,&15

Answer 1

Hey

Here is your answer,

LCM = 90

But, 2 and 5 are not in pair.
Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).
= 90 × 2 × 5
= 90 × 10
= 900

Hence,
Required smallest square no. that's divisible by 6, 9 and 15 = 900

Hope it helps you!