find the least square number divisible by each one of the digits 8, 9 and 10
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Answer:
Ans is 3600.
Step-by-step explanation:
LCM of 8,9,10 is - 2*2*2*2*3*3*5 = 360
Now we can see that in the LCM we got one 2 and 5 which are not in pair so, we will multiple the LCM of 8,9,10 that is 360 by 2 and 5
360*2*5 = 3600
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Answered by
2
The smallest square number divisible by 8,9,10=3600.
LCM=2*2*2*3*3*5=360
Since 2 and 5 are not in pair multiply 2and 5 to make it a perfect square.
The required number =360*2*5=3600
Then answer becomes 3600..ANSWER
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