Math, asked by kallapons, 9 months ago

find the least square number divisible by each one of the digits 8, 9 and 10 ​

Answers

Answered by Anonymous
3

Answer:

Ans is 3600.

Step-by-step explanation:

LCM of 8,9,10 is - 2*2*2*2*3*3*5 = 360

Now we can see that in the LCM we got one 2 and 5 which are not in pair so, we will multiple the LCM of 8,9,10 that is 360 by 2 and 5

360*2*5 = 3600

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Answered by avani1396
2

The smallest square number divisible by 8,9,10=3600.

LCM=2*2*2*3*3*5=360

Since 2 and 5 are not in pair multiply 2and 5 to make it a perfect square.

The required number =360*2*5=3600

Then answer becomes 3600..ANSWER

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