Question

Find the least square number divisible by first four prime numbers.​

Answer 1

Answer:

the first four prime numbers are 2,3,5,7

thus the required no.=(2*3*5*7)^2

=210^2=44100

( here * means multiplecation)

Answer 2

Answer:

Here is your answer mate

Step-by-step explanation:

The first four prime numbers are 2,3,5,7.

Thus the required no = 2 * 3 * 5 * 7 raised to the power of 2

(Mate, I don't have the symbol that's why I am writing in words)

2 * 3 * 5 * 7 = 210 and,

210 raised to the power of 2 is 44100.

So, the answer is 44100.

Hope it helps

Plz mark me as BRAINLIEST.