Math, asked by wadhwamukesh587, 3 months ago

Find the least square number exactly divisible by each one of the numbers 6,8, and 16​

Answers

Answered by Taekook177
18

Step-by-step explanation:

So, in LCM = 2⁴ * 3 = 2² * 2² * 3 as we can 3 is only one time. we can conclude that, we must multiply the LCM with 3 in order to make it a perfect Square. Therefore, → Required Number = 2² * 2² * 3 * 3 = 4 * 4 * 9 = 144

Answered by Bala7600
4

Step-by-step explanation:

As we know that, to find the least Number which can be exactly divisible by each one of the given numbers is LCM of all the given Numbers.

So,

Prime Factors of 6, 8 and 16 :-

→ 6 = 2¹ * 3¹

→ 8 = 2 * 2 * 2 = 2³

→ 16 = 2 * 2 * 2 * 2 = 2⁴

LCM :- 2⁴ * 3

Now, we have to find Least Square number .

we know that, any number to be a perfect Square , it must be pair of Prime factors .

So, in LCM = 2⁴ * 3 = 2² * 2² * 3 as we can 3 is only one time.

we can conclude that, we must multiply the LCM with 3 in order to make it a perfect Square.

Therefore,

→ Required Number = 2² * 2² * 3 * 3 = 4 * 4 * 9 = 144 (Ans.)

Hence, 144 is the Least square number exactly divisible by each one of the numbers 6,8,16.

___________________

Note :- if it is asked find the Square root of the resulting number , either we find Square root of 144 or we just take one digit from each pair and multiply . Ex :- 2 * 2 * 3 = 12 (Ans.)

_________________________

Similar questions