Question

Find the least square number which is divisible by each of the number 4, 8 and 12.

Answer 1

$here \: we \: have \: to \: find \: l.c.m. \\ \\ prime \: factors \: of \: ... \\ \\ 4 = 2 \times 2 \times 1 \\ 8 = 2 \times 2 \times 2 \times 1 \\ 12 = 2 \times 2 \times 3 \times 1 \\ \\ l.c.m. = 2 \times 2 \times 2 \times 3 \\ \: \: \: \: \: \: \: = 24$

MARK AS BRAINLIST.....!!!

Answer 2

Answer:

Think about it: you need a common multiple of 4, 8 and 12 that is also a square number.

Our first 12 square numbers:

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144

Now, you could go through your multiplication tables, but first off, get shot of your odd numbers (since all multiples of 4, 8 and 12 are even numbers), and we’re left with:

4, 16, 36, 64, 100, 144

Great. Now rule out anything that doesn’t divide by 12, since that’s a far bigger list, and we’re left with:

36, 144

Now anything that doesn’t divide by 8, and we’re left with:

144.

We can also check this:

144 / 4 = 36

144/ 8 = 18

144 / 12 = 12

Since 144 divides into all three without a remainder, that’s our answer.

Hope it helps

Mark as brainliest plz