Question

Find the least three digit number which when divided by 20, 30, 40, and 50
leaves a remainder 10 in each case. ​

Answer 1

Answer:

610

Hence, the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case is 610

Step-by-step explanation:

20 = 1 × 2 × 2 × 5 = 22 × 51

30 = 1 × 2 × 3 × 5 = 21 × 31 × 51

40 = 1 × 2 × 2 × 2 × 5 = 23 × 51

50 = 1 × 2 × 5 × 5 = 21 × 52

LCM of 20, 30, 40 and 50 = 23 × 31 × 52 = 600

∴ Required number = 600 + 10 = 610.

Hence, the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case is 610.

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