Math, asked by pmrenikareddy, 7 months ago

Find the least value of 3sinx-4cosx + 7​

Answers

Answered by sunaina9378
0

Answer:

Answers : (1)

maximum value is = (a2 + b2)

while minimu value is = – (a2 + b2)

maximum value is = (32 + 42) – 7 = 5 –7 = –2.

minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.

Step-by-step explanation:

Answers : (1)

maximum value is = (a2 + b2)

while minimu value is = – (a2 + b2)

maximum value is = (32 + 42) – 7 = 5 –7 = –2.

minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.

Answered by anshu6313
0

Answer:

= √25 + 7.

= 12.

= -√25 + 7.

= 2.

So the minimum value is 2 and maximum value is 12.

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