Find the least value of 3sinx-4cosx + 7
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0
Answer:
Answers : (1)
maximum value is = (a2 + b2)
while minimu value is = – (a2 + b2)
maximum value is = (32 + 42) – 7 = 5 –7 = –2.
minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.
Step-by-step explanation:
Answers : (1)
maximum value is = (a2 + b2)
while minimu value is = – (a2 + b2)
maximum value is = (32 + 42) – 7 = 5 –7 = –2.
minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.
Answered by
0
Answer:
= √25 + 7.
= 12.
= -√25 + 7.
= 2.
So the minimum value is 2 and maximum value is 12.
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