Math, asked by ayushyadavsr1731, 1 month ago

Find the least value of “a” so that 36a20 is divisible by “3”?​

Answers

Answered by harshitamishra2006
0

Answer:

1

Step-by-step explanation:

3+6+a+2+0

11+a

least value of “a” is 1.

Answered by bhuvna789456
0

The least value of a will be 1

Step-by-step explanation:

=> The divisibility test of 3 states that, the sum of all digits of a number must be divisible by 3.

Therefore here the given number is 36a20

Adding all the digits of this number :

3 + 6 + a + 2 + 0

11 + a

The sum of digits must be divisible by 3 to satisfy the divisibility test.

Therefore 11 + a should be divisible by 3 that is, it should be a multiple of 3.

So the multiple of 3 nearest to 11 is 12

Therefore 11 + a = 12

So the value of a is 1.

Therefore the number will be 36120

Verifying the answer obtained,

Sum of digits = 3 + 6  + 1 + 2 + 0 = 12

12 is divisible by 3

Therefore the number is divisible by 3.

Similar questions