Question

find the least value of 'b' in 900+10b +6 to make it divisible by both 3 and 9

Answer 1

Answer:

3

Step-by-step explanation:

Given  

find the least value of 'b' in 900+10 b +6 to make it divisible by both 3 and 9

A number is divisible by 3 or 9 if t he sum of its digits is divisible by 9 or 3

We need to find the least value of b to be divisible by 3 and 9.

By trial and error method we get

If  b = 1, then it is 916 which is not divisible by 9

If b = 2 then it is 926 which is not divisible by 3 and 9

If b = 3, then it is 936 which is divisible by bot h 3 and 9