Math, asked by sampathkumar6753, 8 months ago

Find the least value of
COS²x+sec²x

Answers

Answered by souravsarkar045

0

Answer:

least value = 2

Step-by-step explanation:

${cos}^{2} x + {sec}^{2} x \\ = {(cosx - secx})^{2} + 2cosx.secx \\ = 0 + 2 \times 1 \\ = 2$

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