Question

Find the least value of
COS²x+sec²x​

Answer 1

Answer:

least value = 2

Step-by-step explanation:

${cos}^{2} x + {sec}^{2} x \\ = {(cosx - secx})^{2} + 2cosx.secx \\ = 0 + 2 \times 1 \\ = 2$