Question

Find the least value of k for which the quadratic equation - 3x square - 6x+k=0 has equal roots​

Answer 1

Answer:

k=3

Step-by-step explanation:

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Answer 2

The least value of k is 3.

Explanation:

We know that if a quadratic equation $ax^2+bx+c=0$ has equal roots , then its discriminant is 0 .

Discriminant= $d=\sqrt{b^2-4ac}=0$    (1)

The given quadratic equation that has equal roots = $3x^2-6x+k=0$ , where a= 3 , b= -6 and c=k

Put all corresponding values in (1) , we get

$\sqrt{(-6)^2-4(3)(k)}=0\\\\ \sqrt{36-12k}=0\\\\ 36-12k=0\\\\ 12k=36\\\\ k=3$

Hence, the least value of k is 3.

# Learn more :

Find the nature of the roots of the quadratic equation 3x²-4x+5=0, also change the coefficient of X in the given quadratic equation, such that it has equal roots

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