Question

find the least which when divided by 36,24 and 48 leaves remainder 33,21 and 45 respectively.

Answer 1

Take the LCM of .36, 24, 48

36 = 2×2×3×3
24= 2×2×2×3
48= 2×2×2×2×3

LCM = 2^4 × 3^2
LCM = 16×9
LCM = 144

now

difference in The remainder in each number is 3
36-33 => 3
24-21=> 3
48-45 => 3

so
144-3 = 141
Ans

Answer 2

hi


aim : to find Find the least which when divided by 36,24 and 48 leaves remainder 33,21 and 45 respectively

lcm of 36,24 and 28

=>  144

144/36  = 4

144/ 24=  6

144/48 = 3

now let us detect

36 - 33 = 3

24 - 21 = 3

48 - 45 = 3

now hcf of 3,3,3, = 3

so 144-3 

= >141

hecne the answer is 141

hope it helps u

:)