Math, asked by himanshihotchandani8, 1 month ago

Find the leat number which when divided by 6 15 and 18 leaves remainder 5 in each case​

Answers

Answered by NikhilPrajapati99200
0

Answer:

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Answered by asmitkumar2255
1

Find the L.C.M of 6, 15, and 18

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5

L.C.M (6, 15 and 18) = 90

Therefore, the required number = 90+5 = 95

As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

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