Find the leat number which when divided by 6 15 and 18 leaves remainder 5 in each case
Answers
Answered by
0
Answer:
please mark me as a brainliest
Answered by
1
Find the L.C.M of 6, 15, and 18
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
Similar questions
Computer Science,
21 days ago
Computer Science,
21 days ago
Math,
21 days ago
Math,
1 month ago
Math,
1 month ago
English,
9 months ago
History,
9 months ago