Question

find the leatest number by which 9408 must be divided to get perfect square

Answer 1

nahi pata agar pta bhi hota toh nhi batata mai khud padhu ya dusro ko bataun

Answer 2

Prime factorization of 9408:

9408 = 2*4704

         = 2*2*2352

         = 2*2*2*1176

         = 2*2*2*2*588

         = 2*2*2*2*2*294

         = 2*2*2*2*2*2*147

         = 2*2*2*2*2*2*3*49

         = 2*2*2*2*2*2*3*7*7

         = 2⁶ * 7² * 3¹

For a number to be perfect square the powers in its factorized form should be divisible by 2. Hence if we divide by 3 the remaining part is perfect square

3 is the least number required